| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.88 |
| Score | 0% | 58% |
Which of the following statements about parallel lines with a transversal is not correct?
same-side interior angles are complementary and equal each other |
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angles in the same position on different parallel lines are called corresponding angles |
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all acute angles equal each other |
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all of the angles formed by a transversal are called interior angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
If BD = 15 and AD = 22, AB = ?
| 11 | |
| 7 | |
| 8 | |
| 9 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDFor this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c2 - a2 |
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a2 - c2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Solve for x:
3x + 7 < \( \frac{x}{1} \)
| x < \(\frac{6}{19}\) | |
| x < -\(\frac{4}{5}\) | |
| x < -3\(\frac{1}{2}\) | |
| x < -\(\frac{5}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3x + 7 < \( \frac{x}{1} \)
1 x (3x + 7) < x
(1 x 3x) + (1 x 7) < x
3x + 7 < x
3x + 7 - x < 0
3x - x < -7
2x < -7
x < \( \frac{-7}{2} \)
x < -3\(\frac{1}{2}\)
If side x = 10cm, side y = 11cm, and side z = 12cm what is the perimeter of this triangle?
| 30cm | |
| 28cm | |
| 33cm | |
| 21cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 10cm + 11cm + 12cm = 33cm