ASVAB Math Knowledge Practice Test 625654

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7b + b = -7b + 7z - 2 for b in terms of z.

-\(\frac{1}{3}\)z + \(\frac{1}{3}\)
1\(\frac{1}{2}\)z - 1\(\frac{1}{6}\)
\(\frac{3}{7}\)z - \(\frac{1}{7}\)
\(\frac{1}{7}\)z - \(\frac{4}{7}\)