When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 8c = -c + 2y - 3 for c in terms of y.
| -\(\frac{1}{10}\)y + \(\frac{1}{10}\) | |
| -1\(\frac{1}{4}\)y + 1\(\frac{1}{4}\) | |
| -\(\frac{1}{2}\)y + 1\(\frac{1}{4}\) | |
| -1\(\frac{1}{2}\)y - \(\frac{3}{4}\) |