ASVAB Math Knowledge Practice Test 627882

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9c + 3c = -c - 2y - 4 for c in terms of y.

1\(\frac{1}{6}\)y - \(\frac{1}{3}\)
\(\frac{1}{11}\)y + \(\frac{9}{11}\)
-1\(\frac{1}{6}\)y + 1\(\frac{1}{6}\)
\(\frac{5}{8}\)y + \(\frac{1}{2}\)