ASVAB Math Knowledge Practice Test 628997

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + 7a = -3a + 4z - 5 for a in terms of z.

\(\frac{2}{13}\)z + \(\frac{1}{13}\)
\(\frac{1}{3}\)z + \(\frac{2}{3}\)
z + 1\(\frac{2}{3}\)
\(\frac{5}{6}\)z + \(\frac{1}{6}\)