When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 2c = 3c - x + 9 for c in terms of x.
| -1\(\frac{2}{3}\)x + 1\(\frac{2}{3}\) | |
| \(\frac{2}{5}\)x + 1\(\frac{3}{5}\) | |
| 3x - 9 | |
| -\(\frac{4}{9}\)x + 1 |