When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 8c = -6c + 9z - 1 for c in terms of z.
| -\(\frac{5}{6}\)z - \(\frac{2}{3}\) | |
| 1\(\frac{5}{12}\)z - \(\frac{1}{12}\) | |
| \(\frac{4}{7}\)z - \(\frac{1}{7}\) | |
| 2\(\frac{2}{5}\)z - 1\(\frac{3}{5}\) |