| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
Which of the following statements about math operations is incorrect?
you can subtract monomials that have the same variable and the same exponent |
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all of these statements are correct |
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you can add monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Solve for x:
-7x + 2 < 4 + 4x
| x < \(\frac{1}{4}\) | |
| x < -\(\frac{2}{11}\) | |
| x < 1\(\frac{2}{7}\) | |
| x < -1\(\frac{1}{6}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-7x + 2 < 4 + 4x
-7x < 4 + 4x - 2
-7x - 4x < 4 - 2
-11x < 2
x < \( \frac{2}{-11} \)
x < -\(\frac{2}{11}\)
This diagram represents two parallel lines with a transversal. If y° = 141, what is the value of w°?
| 39 | |
| 141 | |
| 36 | |
| 19 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 141, the value of w° is 39.
Which of the following is not true about both rectangles and squares?
the area is length x width |
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the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
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all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
Solve for c:
3c + 6 = 7 - 2c
| \(\frac{1}{7}\) | |
| -1\(\frac{1}{3}\) | |
| \(\frac{1}{5}\) | |
| -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
3c + 6 = 7 - 2c
3c = 7 - 2c - 6
3c + 2c = 7 - 6
5c = 1
c = \( \frac{1}{5} \)
c = \(\frac{1}{5}\)