ASVAB Math Knowledge Practice Test 633401 Results

Your Results Global Average
Questions 5 5
Correct 0 3.68
Score 0% 74%

Review

1

This diagram represents two parallel lines with a transversal. If a° = 32, what is the value of z°?

73% Answer Correctly
32
163
152
13

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with a° = 32, the value of z° is 32.


2

What is the area of a circle with a diameter of 4?

69% Answer Correctly
81π
36π
49π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{4}{2} \)
r = 2
a = πr2
a = π(22)
a = 4π


3

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

exponents

pairs

division

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


4

What is 3a + 9a?

81% Answer Correctly
12
-6
-6a2
12a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a + 9a = 12a


5

Solve for b:
b - 4 < 5 - 7b

55% Answer Correctly
b < -2
b < -1
b < 1\(\frac{1}{4}\)
b < 1\(\frac{1}{8}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

b - 4 < 5 - 7b
b < 5 - 7b + 4
b + 7b < 5 + 4
8b < 9
b < \( \frac{9}{8} \)
b < 1\(\frac{1}{8}\)