| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
The endpoints of this line segment are at (-2, 3) and (2, 5). What is the slope-intercept equation for this line?
| y = 2x + 4 | |
| y = -2x - 4 | |
| y = \(\frac{1}{2}\)x - 3 | |
| y = \(\frac{1}{2}\)x + 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, 5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(5.0) - (3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x + 4
Find the value of c:
8c + y = 3
2c + 4y = -7
| 1\(\frac{2}{5}\) | |
| 1\(\frac{1}{67}\) | |
| \(\frac{19}{30}\) | |
| 1\(\frac{1}{2}\) |
You need to find the value of c so solve the first equation in terms of y:
8c + y = 3
y = 3 - 8c
then substitute the result (3 - 8c) into the second equation:
2c + 4(3 - 8c) = -7
2c + (4 x 3) + (4 x -8c) = -7
2c + 12 - 32c = -7
2c - 32c = -7 - 12
-30c = -19
c = \( \frac{-19}{-30} \)
c = \(\frac{19}{30}\)
A trapezoid is a quadrilateral with one set of __________ sides.
right angle |
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parallel |
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equal angle |
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equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
A quadrilateral is a shape with __________ sides.
2 |
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5 |
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4 |
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3 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
A(n) __________ is to a parallelogram as a square is to a rectangle.
quadrilateral |
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rhombus |
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trapezoid |
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triangle |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.