When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4a + 6a = 8a + 3z + 3 for a in terms of z.
| \(\frac{1}{4}\)z - \(\frac{1}{4}\) | |
| 2\(\frac{1}{6}\)z - 1 | |
| -5z - 8 | |
| -z + \(\frac{5}{8}\) |