ASVAB Math Knowledge Practice Test 634932

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3a + 6a = 6a - 5y - 9 for a in terms of y.

\(\frac{1}{2}\)y - 2\(\frac{1}{2}\)
3\(\frac{2}{3}\)y + 3
1\(\frac{4}{5}\)y - \(\frac{2}{5}\)
8y + 1