ASVAB Math Knowledge Practice Test 636316 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

If the base of this triangle is 5 and the height is 2, what is the area?

58% Answer Correctly
36
5
58\(\frac{1}{2}\)
56

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 5 x 2 = \( \frac{10}{2} \) = 5


2

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

squaring

factoring

normalizing

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


3

The endpoints of this line segment are at (-2, -1) and (2, 9). What is the slope of this line?

46% Answer Correctly
-\(\frac{1}{2}\)
\(\frac{1}{2}\)
1
2\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -1) and (2, 9) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(9.0) - (-1.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)
m = 2\(\frac{1}{2}\)


4

If c = 4 and y = -4, what is the value of -9c(c - y)?

68% Answer Correctly
-288
192
-60
630

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-9c(c - y)
-9(4)(4 + 4)
-9(4)(8)
(-36)(8)
-288


5

Solve for b:
-3b - 7 < -4 + 8b

54% Answer Correctly
b < -\(\frac{3}{11}\)
b < -3
b < \(\frac{1}{3}\)
b < -2\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-3b - 7 < -4 + 8b
-3b < -4 + 8b + 7
-3b - 8b < -4 + 7
-11b < 3
b < \( \frac{3}{-11} \)
b < -\(\frac{3}{11}\)