| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
A cylinder with a radius (r) and a height (h) has a surface area of:
4π r2 |
|
π r2h2 |
|
2(π r2) + 2π rh |
|
π r2h |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve for z:
-2z + 9 = \( \frac{z}{4} \)
| 4 | |
| -1\(\frac{1}{27}\) | |
| 1\(\frac{1}{20}\) | |
| \(\frac{21}{26}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-2z + 9 = \( \frac{z}{4} \)
4 x (-2z + 9) = z
(4 x -2z) + (4 x 9) = z
-8z + 36 = z
-8z + 36 - z = 0
-8z - z = -36
-9z = -36
z = \( \frac{-36}{-9} \)
z = 4
If a = c = 4, b = d = 3, and the blue angle = 68°, what is the area of this parallelogram?
| 2 | |
| 32 | |
| 16 | |
| 12 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 4 x 3
a = 12
Solve for z:
z2 - 3z - 29 = -z - 5
| -4 or 6 | |
| 9 or -1 | |
| -2 or -4 | |
| 3 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 - 3z - 29 = -z - 5
z2 - 3z - 29 + 5 = -z
z2 - 3z + z - 24 = 0
z2 - 2z - 24 = 0
Next, factor the quadratic equation:
z2 - 2z - 24 = 0
(z + 4)(z - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 4) or (z - 6) must equal zero:
If (z + 4) = 0, z must equal -4
If (z - 6) = 0, z must equal 6
So the solution is that z = -4 or 6
If a = c = 5, b = d = 3, what is the area of this rectangle?
| 12 | |
| 15 | |
| 40 | |
| 7 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 5 x 3
a = 15