ASVAB Math Knowledge Practice Test 640311

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4c + 4c = -4c - 2z + 4 for c in terms of z.

-\(\frac{3}{4}\)z + \(\frac{1}{2}\)
-\(\frac{1}{7}\)z - \(\frac{1}{2}\)
\(\frac{5}{7}\)z - \(\frac{4}{7}\)
-\(\frac{11}{13}\)z - \(\frac{6}{13}\)