ASVAB Math Knowledge Practice Test 641352 Results

Your Results Global Average
Questions 5 5
Correct 0 2.71
Score 0% 54%

Review

1

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

acute, right, obtuse

right, obtuse, acute

right, acute, obtuse

acute, obtuse, right


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


2

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

trisects

intersects

bisects

midpoints


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

The dimensions of this cylinder are height (h) = 5 and radius (r) = 2. What is the surface area?

48% Answer Correctly
24π
156π
48π
28π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 5)
sa = 2π(4) + 2π(10)
sa = (2 x 4)π + (2 x 10)π
sa = 8π + 20π
sa = 28π


4

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

a parallelogram is a quadrilateral

opposite sides and adjacent angles are equal

the perimeter of a parallelogram is the sum of the lengths of all sides

the area of a parallelogram is base x height


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


5

Factor y2 + 2y - 3

54% Answer Correctly
(y + 1)(y - 3)
(y - 1)(y - 3)
(y - 1)(y + 3)
(y + 1)(y + 3)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -3 as well and sum (Inside, Outside) to equal 2. For this problem, those two numbers are -1 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 2y - 3
y2 + (-1 + 3)y + (-1 x 3)
(y - 1)(y + 3)