When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 6c = 5c + 8x + 4 for c in terms of x.
| \(\frac{1}{2}\)x + 1 | |
| -\(\frac{5}{12}\)x - \(\frac{1}{6}\) | |
| -x - 2 | |
| 3\(\frac{2}{3}\)x - 1\(\frac{1}{3}\) |