When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c + 5c = -4c - 2z + 8 for c in terms of z.
| -3\(\frac{1}{2}\)z + 4 | |
| -\(\frac{3}{7}\)z + \(\frac{5}{7}\) | |
| \(\frac{1}{10}\)z - \(\frac{3}{10}\) | |
| 2z + \(\frac{5}{6}\) |