When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c - 2c = -8c + 3z + 6 for c in terms of z.
| 1\(\frac{1}{5}\)z + 1\(\frac{3}{5}\) | |
| \(\frac{5}{17}\)z + \(\frac{6}{17}\) | |
| 5\(\frac{1}{3}\)z - \(\frac{2}{3}\) | |
| -10z - 5 |