ASVAB Math Knowledge Practice Test 64498

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 10a + 8a = 9a + 4z - 3 for a in terms of z.

z + 1
-\(\frac{11}{14}\)z - \(\frac{1}{7}\)
-4z - 3
1\(\frac{8}{9}\)z - \(\frac{2}{3}\)