| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
|
slope |
|
x-intercept |
|
\({\Delta y \over \Delta x}\) |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
This diagram represents two parallel lines with a transversal. If z° = 14, what is the value of a°?
| 170 | |
| 35 | |
| 14 | |
| 12 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with z° = 14, the value of a° is 14.
Solve for c:
-7c + 5 = 6 - 9c
| 1\(\frac{2}{3}\) | |
| \(\frac{1}{2}\) | |
| -\(\frac{1}{2}\) | |
| 4 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-7c + 5 = 6 - 9c
-7c = 6 - 9c - 5
-7c + 9c = 6 - 5
2c = 1
c = \( \frac{1}{2} \)
c = \(\frac{1}{2}\)
Simplify (5a)(7ab) + (3a2)(7b).
| -14a2b | |
| 120ab2 | |
| 56a2b | |
| 14a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(7ab) + (3a2)(7b)
(5 x 7)(a x a x b) + (3 x 7)(a2 x b)
(35)(a1+1 x b) + (21)(a2b)
35a2b + 21a2b
56a2b
Solve for a:
8a - 8 > -3 - 2a
| a > \(\frac{5}{7}\) | |
| a > \(\frac{1}{2}\) | |
| a > \(\frac{8}{9}\) | |
| a > \(\frac{1}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
8a - 8 > -3 - 2a
8a > -3 - 2a + 8
8a + 2a > -3 + 8
10a > 5
a > \( \frac{5}{10} \)
a > \(\frac{1}{2}\)