ASVAB Math Knowledge Practice Test 645547 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

The dimensions of this cylinder are height (h) = 4 and radius (r) = 7. What is the volume?

63% Answer Correctly
196π
567π
441π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(72 x 4)
v = 196π


2

Which of the following statements about a triangle is not true?

58% Answer Correctly

area = ½bh

sum of interior angles = 180°

exterior angle = sum of two adjacent interior angles

perimeter = sum of side lengths


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


3

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

formula

problem

expression

equation


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

supplementary, vertical

obtuse, acute

acute, obtuse

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


5

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
9\( \sqrt{2} \)
2\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)