ASVAB Math Knowledge Practice Test 648637 Results

Your Results Global Average
Questions 5 5
Correct 0 2.90
Score 0% 58%

Review

1

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

First

Odd

Last

Inside


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


2

Solve for y:
6y - 6 = \( \frac{y}{5} \)

46% Answer Correctly
1\(\frac{1}{29}\)
-2\(\frac{2}{3}\)
-1\(\frac{7}{11}\)
-\(\frac{7}{18}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

6y - 6 = \( \frac{y}{5} \)
5 x (6y - 6) = y
(5 x 6y) + (5 x -6) = y
30y - 30 = y
30y - 30 - y = 0
30y - y = 30
29y = 30
y = \( \frac{30}{29} \)
y = 1\(\frac{1}{29}\)


3

Solve for z:
z2 - z - 42 = 0

58% Answer Correctly
5 or 5
8 or -6
3 or 1
-6 or 7

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 - z - 42 = 0
(z + 6)(z - 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 6) or (z - 7) must equal zero:

If (z + 6) = 0, z must equal -6
If (z - 7) = 0, z must equal 7

So the solution is that z = -6 or 7


4

The dimensions of this cube are height (h) = 8, length (l) = 3, and width (w) = 8. What is the surface area?

51% Answer Correctly
224
46
184
80

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 3 x 8) + (2 x 8 x 8) + (2 x 3 x 8)
sa = (48) + (128) + (48)
sa = 224


5

The dimensions of this cylinder are height (h) = 2 and radius (r) = 1. What is the surface area?

48% Answer Correctly
176π
88π
10π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 2)
sa = 2π(1) + 2π(2)
sa = (2 x 1)π + (2 x 2)π
sa = 2π + 4π
sa = 6π