ASVAB Math Knowledge Practice Test 649257

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + 2a = 2a + 4z - 3 for a in terms of z.

-\(\frac{1}{4}\)z + \(\frac{3}{8}\)
1\(\frac{5}{6}\)z + 1\(\frac{1}{6}\)
\(\frac{3}{5}\)z - \(\frac{3}{5}\)
7z + 5