When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 3c = 5c - 2x - 1 for c in terms of x.
| x + \(\frac{7}{12}\) | |
| -5x - 1 | |
| -\(\frac{11}{14}\)x - \(\frac{3}{7}\) | |
| x + \(\frac{4}{5}\) |