ASVAB Math Knowledge Practice Test 650528

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -a - a = -3a - 3y + 2 for a in terms of y.

\(\frac{2}{5}\)y + 1\(\frac{4}{5}\)
y - 1\(\frac{1}{3}\)
-y + 1
-\(\frac{3}{5}\)y + \(\frac{2}{5}\)