When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3b - 2b = -6b - 4z - 5 for b in terms of z.
| \(\frac{7}{15}\)z - \(\frac{3}{5}\) | |
| \(\frac{1}{8}\)z + \(\frac{3}{8}\) | |
| 1\(\frac{2}{9}\)z + \(\frac{1}{3}\) | |
| -\(\frac{2}{3}\)z - 1\(\frac{2}{3}\) |