| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
exponents |
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division |
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addition |
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pairs |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2b + 7b = 6b + 5z - 7 for b in terms of z.
| z + 7 | |
| 1\(\frac{1}{10}\)z + \(\frac{3}{5}\) | |
| 1\(\frac{1}{2}\)z - 3\(\frac{1}{2}\) | |
| \(\frac{1}{4}\)z + \(\frac{7}{8}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-2b + 7z = 6b + 5z - 7
-2b = 6b + 5z - 7 - 7z
-2b - 6b = 5z - 7 - 7z
-8b = -2z - 7
b = \( \frac{-2z - 7}{-8} \)
b = \( \frac{-2z}{-8} \) + \( \frac{-7}{-8} \)
b = \(\frac{1}{4}\)z + \(\frac{7}{8}\)
Which of the following expressions contains exactly two terms?
polynomial |
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monomial |
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binomial |
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quadratic |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
The endpoints of this line segment are at (-2, -2) and (2, -4). What is the slope-intercept equation for this line?
| y = 2x - 1 | |
| y = x - 2 | |
| y = -\(\frac{1}{2}\)x - 3 | |
| y = -\(\frac{1}{2}\)x + 0 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)Plugging these values into the slope-intercept equation:
y = -\(\frac{1}{2}\)x - 3
Simplify (7a)(5ab) - (5a2)(5b).
| 120ab2 | |
| 60a2b | |
| 10a2b | |
| 60ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(5ab) - (5a2)(5b)
(7 x 5)(a x a x b) - (5 x 5)(a2 x b)
(35)(a1+1 x b) - (25)(a2b)
35a2b - 25a2b
10a2b