When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 6c = 4c - 4z + 8 for c in terms of z.
| -z + 2\(\frac{1}{2}\) | |
| 1\(\frac{1}{10}\)z - \(\frac{3}{5}\) | |
| 1\(\frac{1}{2}\)z - 1 | |
| -2z + 1\(\frac{3}{5}\) |