When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 8c = -4c - 8y - 6 for c in terms of y.
y - 1 | |
-3\(\frac{3}{4}\)y - 1\(\frac{1}{2}\) | |
y + 2\(\frac{1}{3}\) | |
-13y - 1 |