When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -b + 2b = b - 6z + 6 for b in terms of z.
| \(\frac{4}{13}\)z - \(\frac{6}{13}\) | |
| -12z - 5 | |
| 4z - 3 | |
| 2\(\frac{2}{3}\)z - 1\(\frac{2}{3}\) |