| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.68 |
| Score | 0% | 54% |
If the length of AB equals the length of BD, point B __________ this line segment.
midpoints |
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intersects |
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bisects |
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trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Solve for b:
-b + 1 > \( \frac{b}{-5} \)
| b > \(\frac{48}{71}\) | |
| b > -3\(\frac{1}{5}\) | |
| b > -\(\frac{16}{73}\) | |
| b > 1\(\frac{1}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-b + 1 > \( \frac{b}{-5} \)
-5 x (-b + 1) > b
(-5 x -b) + (-5 x 1) > b
5b - 5 > b
5b - 5 - b > 0
5b - b > 5
4b > 5
b > \( \frac{5}{4} \)
b > 1\(\frac{1}{4}\)
If the area of this square is 9, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
On this circle, line segment CD is the:
chord |
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radius |
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circumference |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Simplify (4a)(4ab) + (2a2)(6b).
| 4ab2 | |
| 28a2b | |
| -4a2b | |
| -4ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(4ab) + (2a2)(6b)
(4 x 4)(a x a x b) + (2 x 6)(a2 x b)
(16)(a1+1 x b) + (12)(a2b)
16a2b + 12a2b
28a2b