When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - c = 5c - 3z - 9 for c in terms of z.
| -4\(\frac{2}{3}\)z + 1 | |
| -2z - 9 | |
| -\(\frac{2}{9}\)z - \(\frac{8}{9}\) | |
| 2\(\frac{1}{2}\)z + \(\frac{1}{6}\) |