| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.88 |
| Score | 0% | 58% |
Which of the following is not true about both rectangles and squares?
the area is length x width |
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all interior angles are right angles |
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the lengths of all sides are equal |
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the perimeter is the sum of the lengths of all four sides |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
The formula for the area of a circle is which of the following?
a = π r |
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a = π r2 |
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a = π d |
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a = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve 9c + 2c = -5c - 8y + 4 for c in terms of y.
| -\(\frac{1}{5}\)y - \(\frac{2}{5}\) | |
| \(\frac{1}{14}\)y + \(\frac{3}{14}\) | |
| y + \(\frac{1}{4}\) | |
| -\(\frac{5}{7}\)y + \(\frac{2}{7}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
9c + 2y = -5c - 8y + 4
9c = -5c - 8y + 4 - 2y
9c + 5c = -8y + 4 - 2y
14c = -10y + 4
c = \( \frac{-10y + 4}{14} \)
c = \( \frac{-10y}{14} \) + \( \frac{4}{14} \)
c = -\(\frac{5}{7}\)y + \(\frac{2}{7}\)
Simplify (4a)(2ab) + (6a2)(3b).
| 26ab2 | |
| -10a2b | |
| 26a2b | |
| 10ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(2ab) + (6a2)(3b)
(4 x 2)(a x a x b) + (6 x 3)(a2 x b)
(8)(a1+1 x b) + (18)(a2b)
8a2b + 18a2b
26a2b
Solve for b:
b2 - 8b - 3 = -3b + 3
| 8 or 2 | |
| -1 or 6 | |
| 9 or -9 | |
| -2 or -8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 8b - 3 = -3b + 3
b2 - 8b - 3 - 3 = -3b
b2 - 8b + 3b - 6 = 0
b2 - 5b - 6 = 0
Next, factor the quadratic equation:
b2 - 5b - 6 = 0
(b + 1)(b - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 1) or (b - 6) must equal zero:
If (b + 1) = 0, b must equal -1
If (b - 6) = 0, b must equal 6
So the solution is that b = -1 or 6