ASVAB Math Knowledge Practice Test 655856 Results

Your Results Global Average
Questions 5 5
Correct 0 2.88
Score 0% 58%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

all interior angles are right angles

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π r

a = π r2

a = π d

a = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

Solve 9c + 2c = -5c - 8y + 4 for c in terms of y.

34% Answer Correctly
-\(\frac{1}{5}\)y - \(\frac{2}{5}\)
\(\frac{1}{14}\)y + \(\frac{3}{14}\)
y + \(\frac{1}{4}\)
-\(\frac{5}{7}\)y + \(\frac{2}{7}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

9c + 2y = -5c - 8y + 4
9c = -5c - 8y + 4 - 2y
9c + 5c = -8y + 4 - 2y
14c = -10y + 4
c = \( \frac{-10y + 4}{14} \)
c = \( \frac{-10y}{14} \) + \( \frac{4}{14} \)
c = -\(\frac{5}{7}\)y + \(\frac{2}{7}\)


4

Simplify (4a)(2ab) + (6a2)(3b).

65% Answer Correctly
26ab2
-10a2b
26a2b
10ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(2ab) + (6a2)(3b)
(4 x 2)(a x a x b) + (6 x 3)(a2 x b)
(8)(a1+1 x b) + (18)(a2b)
8a2b + 18a2b
26a2b


5

Solve for b:
b2 - 8b - 3 = -3b + 3

48% Answer Correctly
8 or 2
-1 or 6
9 or -9
-2 or -8

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b2 - 8b - 3 = -3b + 3
b2 - 8b - 3 - 3 = -3b
b2 - 8b + 3b - 6 = 0
b2 - 5b - 6 = 0

Next, factor the quadratic equation:

b2 - 5b - 6 = 0
(b + 1)(b - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 1) or (b - 6) must equal zero:

If (b + 1) = 0, b must equal -1
If (b - 6) = 0, b must equal 6

So the solution is that b = -1 or 6