ASVAB Math Knowledge Practice Test 655856

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6b + 3b = 4b + 3z - 8 for b in terms of z.

\(\frac{2}{3}\)z - \(\frac{2}{5}\)
z + \(\frac{4}{5}\)
-\(\frac{5}{13}\)z + \(\frac{5}{13}\)
-1\(\frac{1}{14}\)z + \(\frac{1}{2}\)