To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 2 as well and sum (Inside, Outside) to equal 3. For this problem, those two numbers are 1 and 2. Then, plug these into a set of binomials using the square root of the First variable (y²):

y² + 3y + 2
y² + (1 + 2)y + (1 x 2)
(y + 1)(y + 2)

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.

You need to find the value of c so solve the first equation in terms of y:

-3c + y = 3
y = 3 + 3c

then substitute the result (3 - -3c) into the second equation:

-2c - 7(3 + 3c) = -5
-2c + (-7 x 3) + (-7 x 3c) = -5
-2c - 21 - 21c = -5
-2c - 21c = -5 + 21
-23c = 16
c = \( \frac{16}{-23} \)
c = -\(\frac{16}{23}\)