ASVAB Math Knowledge Practice Test 657195 Results

Your Results Global Average
Questions 5 5
Correct 0 2.76
Score 0% 55%

Review

1

If a = c = 1, b = d = 9, and the blue angle = 75°, what is the area of this parallelogram?

65% Answer Correctly
72
10
9
8

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 1 x 9
a = 9


2

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral, isosceles and right

isosceles and right

equilateral and isosceles

equilateral and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


3

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

problem

expression

equation


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

Solve 9a + 7a = -a - 4z + 7 for a in terms of z.

34% Answer Correctly
-1\(\frac{1}{10}\)z + \(\frac{7}{10}\)
-\(\frac{2}{11}\)z - \(\frac{9}{11}\)
z + 2\(\frac{1}{3}\)
4\(\frac{1}{3}\)z - 1\(\frac{2}{3}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

9a + 7z = -a - 4z + 7
9a = -a - 4z + 7 - 7z
9a + a = -4z + 7 - 7z
10a = -11z + 7
a = \( \frac{-11z + 7}{10} \)
a = \( \frac{-11z}{10} \) + \( \frac{7}{10} \)
a = -1\(\frac{1}{10}\)z + \(\frac{7}{10}\)


5

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

bisects

intersects

midpoints

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.