When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 3c = 3c - 5y + 2 for c in terms of y.
| \(\frac{1}{3}\)y + \(\frac{7}{12}\) | |
| 7y - 1\(\frac{1}{2}\) | |
| 1\(\frac{1}{4}\)y - \(\frac{3}{8}\) | |
| -\(\frac{2}{5}\)y + \(\frac{2}{5}\) |