| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
vertical, supplementary |
|
acute, obtuse |
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supplementary, vertical |
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obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
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right, acute, obtuse |
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right, obtuse, acute |
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acute, obtuse, right |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If BD = 3 and AD = 13, AB = ?
| 16 | |
| 7 | |
| 14 | |
| 10 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf the area of this square is 81, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)
Solve for y:
y2 - 15y + 56 = 0
| 6 or -4 | |
| 7 or 8 | |
| 3 or -3 | |
| 2 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 - 15y + 56 = 0
(y - 7)(y - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 7) or (y - 8) must equal zero:
If (y - 7) = 0, y must equal 7
If (y - 8) = 0, y must equal 8
So the solution is that y = 7 or 8