ASVAB Math Knowledge Practice Test 657999 Results

Your Results Global Average
Questions 5 5
Correct 0 3.35
Score 0% 67%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

vertical, supplementary

acute, obtuse

supplementary, vertical

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

Order the following types of angle from least number of degrees to most number of degrees.

74% Answer Correctly

acute, right, obtuse

right, acute, obtuse

right, obtuse, acute

acute, obtuse, right


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


3

If BD = 3 and AD = 13, AB = ?

75% Answer Correctly
16
7
14
10

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 13 - 3
AB = 10


4

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
2\( \sqrt{2} \)
4\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


5

Solve for y:
y2 - 15y + 56 = 0

57% Answer Correctly
6 or -4
7 or 8
3 or -3
2 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

y2 - 15y + 56 = 0
(y - 7)(y - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 7) or (y - 8) must equal zero:

If (y - 7) = 0, y must equal 7
If (y - 8) = 0, y must equal 8

So the solution is that y = 7 or 8