ASVAB Math Knowledge Practice Test 658150 Results

Your Results Global Average
Questions 5 5
Correct 0 3.46
Score 0% 69%

Review

1

Simplify 8a x 2b.

86% Answer Correctly
10ab
16\( \frac{a}{b} \)
16\( \frac{b}{a} \)
16ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 2b = (8 x 2) (a x b) = 16ab


2

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and isosceles

equilateral, isosceles and right

isosceles and right

equilateral and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


3

Which of the following statements about a triangle is not true?

57% Answer Correctly

area = ½bh

perimeter = sum of side lengths

exterior angle = sum of two adjacent interior angles

sum of interior angles = 180°


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


4

If a = 7, b = 9, c = 6, and d = 6, what is the perimeter of this quadrilateral?

88% Answer Correctly
26
14
28
20

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 7 + 9 + 6 + 6
p = 28


5

Simplify (6a)(2ab) - (4a2)(8b).

62% Answer Correctly
96a2b
96ab2
20ab2
-20a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(2ab) - (4a2)(8b)
(6 x 2)(a x a x b) - (4 x 8)(a2 x b)
(12)(a1+1 x b) - (32)(a2b)
12a2b - 32a2b
-20a2b