When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2b + 3b = -9b + 4z + 6 for b in terms of z.
| -z - 1\(\frac{1}{3}\) | |
| \(\frac{1}{11}\)z + \(\frac{6}{11}\) | |
| \(\frac{1}{16}\)z + \(\frac{1}{16}\) | |
| -1\(\frac{5}{7}\)z + \(\frac{2}{7}\) |