ASVAB Math Knowledge Practice Test 659416 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
8\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


2

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

intersects

midpoints

bisects

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

What is 5a9 + 9a9?

74% Answer Correctly
14a9
14a18
14
45a18

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a9 + 9a9 = 14a9


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

addition

pairs

exponents

division


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

Solve for a:
2a - 7 = -1 - 6a

58% Answer Correctly
\(\frac{3}{4}\)
1\(\frac{1}{8}\)
\(\frac{2}{7}\)
\(\frac{8}{9}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2a - 7 = -1 - 6a
2a = -1 - 6a + 7
2a + 6a = -1 + 7
8a = 6
a = \( \frac{6}{8} \)
a = \(\frac{3}{4}\)