ASVAB Math Knowledge Practice Test 660200 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

right, acute, obtuse

acute, right, obtuse

acute, obtuse, right

right, obtuse, acute


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


2

Solve for b:
-2b - 8 = \( \frac{b}{1} \)

46% Answer Correctly
-2
-2\(\frac{2}{3}\)
2
\(\frac{16}{71}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-2b - 8 = \( \frac{b}{1} \)
1 x (-2b - 8) = b
(1 x -2b) + (1 x -8) = b
-2b - 8 = b
-2b - 8 - b = 0
-2b - b = 8
-3b = 8
b = \( \frac{8}{-3} \)
b = -2\(\frac{2}{3}\)


3

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

the perimeter of a parallelogram is the sum of the lengths of all sides

a parallelogram is a quadrilateral

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


4

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

π r2h

2(π r2) + 2π rh

π r2h2

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

If AD = 14 and BD = 13, AB = ?

75% Answer Correctly
14
1
3
19

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 14 - 13
AB = 1