| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
If angle a = 65° and angle b = 55° what is the length of angle d?
| 115° | |
| 131° | |
| 144° | |
| 112° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 65° - 55° = 60°
So, d° = 55° + 60° = 115°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 65° = 115°
Solve for z:
3z + 1 < \( \frac{z}{-5} \)
| z < -\(\frac{5}{16}\) | |
| z < -\(\frac{14}{57}\) | |
| z < -3 | |
| z < 2 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3z + 1 < \( \frac{z}{-5} \)
-5 x (3z + 1) < z
(-5 x 3z) + (-5 x 1) < z
-15z - 5 < z
-15z - 5 - z < 0
-15z - z < 5
-16z < 5
z < \( \frac{5}{-16} \)
z < -\(\frac{5}{16}\)
Which of the following is not true about both rectangles and squares?
the perimeter is the sum of the lengths of all four sides |
|
all interior angles are right angles |
|
the area is length x width |
|
the lengths of all sides are equal |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
If side x = 7cm, side y = 12cm, and side z = 7cm what is the perimeter of this triangle?
| 26cm | |
| 32cm | |
| 35cm | |
| 17cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 7cm + 12cm + 7cm = 26cm
Solve for x:
x2 - 11x + 28 = -x + 3
| 5 | |
| 5 or -2 | |
| 7 or -5 | |
| -4 or -8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 - 11x + 28 = -x + 3
x2 - 11x + 28 - 3 = -x
x2 - 11x + x + 25 = 0
x2 - 10x + 25 = 0
Next, factor the quadratic equation:
x2 - 10x + 25 = 0
(x - 5)(x - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, (x - 5) must equal zero:
If (x - 5) = 0, x must equal 5
So the solution is that x = 5