When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - 4c = -4c + z - 5 for c in terms of z.
| \(\frac{13}{14}\)z + \(\frac{3}{14}\) | |
| -2\(\frac{1}{2}\)z + 2\(\frac{1}{2}\) | |
| \(\frac{4}{13}\)z + \(\frac{8}{13}\) | |
| z - \(\frac{5}{11}\) |