| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
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A(n) __________ is two expressions separated by an equal sign.
expression |
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problem |
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formula |
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equation |
An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
If c = -1 and x = -1, what is the value of -c(c - x)?
| -162 | |
| 0 | |
| 784 | |
| 90 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-c(c - x)
-1(-1)(-1 + 1)
-1(-1)(0)
(1)(0)
0
Solve for z:
-2z + 4 > \( \frac{z}{6} \)
| z > \(\frac{8}{9}\) | |
| z > \(\frac{2}{5}\) | |
| z > 1\(\frac{11}{13}\) | |
| z > \(\frac{9}{11}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-2z + 4 > \( \frac{z}{6} \)
6 x (-2z + 4) > z
(6 x -2z) + (6 x 4) > z
-12z + 24 > z
-12z + 24 - z > 0
-12z - z > -24
-13z > -24
z > \( \frac{-24}{-13} \)
z > 1\(\frac{11}{13}\)
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
lw x wh + lh |
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h x l x w |
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h2 x l2 x w2 |
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2lw x 2wh + 2lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Solve -9c - 8c = 8c + 2y - 5 for c in terms of y.
| 2y + 7 | |
| y - \(\frac{3}{7}\) | |
| -\(\frac{1}{16}\)y - \(\frac{5}{16}\) | |
| -\(\frac{10}{17}\)y + \(\frac{5}{17}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-9c - 8y = 8c + 2y - 5
-9c = 8c + 2y - 5 + 8y
-9c - 8c = 2y - 5 + 8y
-17c = 10y - 5
c = \( \frac{10y - 5}{-17} \)
c = \( \frac{10y}{-17} \) + \( \frac{-5}{-17} \)
c = -\(\frac{10}{17}\)y + \(\frac{5}{17}\)