When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 3c = 4c - 4x + 5 for c in terms of x.
| \(\frac{8}{13}\)x + \(\frac{9}{13}\) | |
| \(\frac{5}{13}\)x - \(\frac{1}{13}\) | |
| -7x + 5 | |
| \(\frac{1}{4}\)x + \(\frac{1}{12}\) |