| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
On this circle, line segment CD is the:
circumference |
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radius |
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chord |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If a = c = 3, b = d = 7, what is the area of this rectangle?
| 21 | |
| 8 | |
| 42 | |
| 2 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 3 x 7
a = 21
Solve for y:
y2 - 7y + 6 = -3y + 2
| 2 | |
| 5 or 5 | |
| 5 or 1 | |
| -2 or -5 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 - 7y + 6 = -3y + 2
y2 - 7y + 6 - 2 = -3y
y2 - 7y + 3y + 4 = 0
y2 - 4y + 4 = 0
Next, factor the quadratic equation:
y2 - 4y + 4 = 0
(y - 2)(y - 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, (y - 2) must equal zero:
If (y - 2) = 0, y must equal 2
So the solution is that y = 2
Solve for z:
z2 + 16z + 64 = 0
| -6 or -9 | |
| 6 or -4 | |
| -8 | |
| 2 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 16z + 64 = 0
(z + 8)(z + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, (z + 8) must equal zero:
If (z + 8) = 0, z must equal -8
So the solution is that z = -8
Which of the following expressions contains exactly two terms?
binomial |
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quadratic |
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monomial |
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polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.