ASVAB Math Knowledge Practice Test 662309 Results

Your Results Global Average
Questions 5 5
Correct 0 2.74
Score 0% 55%

Review

1

The endpoints of this line segment are at (-2, 0) and (2, 4). What is the slope-intercept equation for this line?

41% Answer Correctly
y = 3x + 1
y = x + 2
y = x + 4
y = 2\(\frac{1}{2}\)x + 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (0.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)
m = 1

Plugging these values into the slope-intercept equation:

y = x + 2


2

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

a2 - c2

c - a

c2 + a2

c2 - a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


3

If BD = 17 and AD = 18, AB = ?

76% Answer Correctly
1
8
18
14

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 18 - 17
AB = 1


4

Solve for y:
y2 - 3y - 40 = 0

58% Answer Correctly
8 or -4
-4 or -7
-5 or 8
-2 or -3

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

y2 - 3y - 40 = 0
(y + 5)(y - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 5) or (y - 8) must equal zero:

If (y + 5) = 0, y must equal -5
If (y - 8) = 0, y must equal 8

So the solution is that y = -5 or 8


5

The dimensions of this trapezoid are a = 6, b = 4, c = 8, d = 7, and h = 5. What is the area?

51% Answer Correctly
13\(\frac{1}{2}\)
16
27\(\frac{1}{2}\)
10

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(4 + 7)(5)
a = ½(11)(5)
a = ½(55) = \( \frac{55}{2} \)
a = 27\(\frac{1}{2}\)