| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
What is the area of a circle with a diameter of 4?
| 9π | |
| 3π | |
| 2π | |
| 4π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{4}{2} \)
r = 2
a = πr2
a = π(22)
a = 4π
The formula for the area of a circle is which of the following?
a = π d |
|
a = π r2 |
|
a = π r |
|
a = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve 2c + 3c = -c - 6z - 8 for c in terms of z.
| -4z + 1 | |
| \(\frac{7}{9}\)z + \(\frac{5}{9}\) | |
| -3z - 2\(\frac{2}{3}\) | |
| -\(\frac{1}{11}\)z + \(\frac{5}{11}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
2c + 3z = -c - 6z - 8
2c = -c - 6z - 8 - 3z
2c + c = -6z - 8 - 3z
3c = -9z - 8
c = \( \frac{-9z - 8}{3} \)
c = \( \frac{-9z}{3} \) + \( \frac{-8}{3} \)
c = -3z - 2\(\frac{2}{3}\)
Solve for x:
6x - 2 > \( \frac{x}{4} \)
| x > \(\frac{8}{23}\) | |
| x > -1\(\frac{13}{23}\) | |
| x > -\(\frac{4}{23}\) | |
| x > \(\frac{40}{49}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6x - 2 > \( \frac{x}{4} \)
4 x (6x - 2) > x
(4 x 6x) + (4 x -2) > x
24x - 8 > x
24x - 8 - x > 0
24x - x > 8
23x > 8
x > \( \frac{8}{23} \)
x > \(\frac{8}{23}\)
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
|
midpoints |
|
bisects |
|
trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.